0 The method to solve such differential equations is Substitute x 2 = u 2 x d x = d u and y 2 = v 2 y d y = d v Then it's neat, a dy/dx = linear/linear type equation is obtained which
3x-y-2=0 2x+y=8 substitution method- Class 7 Science NCERT Solutions Class 8 Science NCERT Solutions Class 9 Science NCERT Solutions Class 10 Science NCERT Solutions Englishtan NCERT Books Class 10 Maths 10 y = 0 Add y to both sides 10 = y (or y = 10) Alan 2 0 Answers #1 10 Best Answer 3x y = 23 (1) 2x 3y = 8 (2) Multiply all terms in (1) by 3 9x 3y =
3x-y-2=0 2x+y=8 substitution methodのギャラリー
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